themadpoker: (Default)
themadpoker ([personal profile] themadpoker) wrote2006-11-02 08:41 pm

I'm a general math idiot

Anyone on my f-list good at math? Working on my homework and I have no clue how to graph inequalities (when it's like y>6+x). *_* I should've asked for more explanation when I was in class.
troisroyaumes: Painting of a duck, with the hanzi for "summer" in the top left (Default)

[personal profile] troisroyaumes 2006-11-03 02:02 am (UTC)(link)
Graph it as an equation first, then shade in the part above or below the curve. E.g. for y > 6 + x, you graph the line y = 6 + x and then shade the region above the line (above because it's greater than; you would shade below if it was y < 6 + x).
troisroyaumes: Painting of a duck, with the hanzi for "summer" in the top left (Default)

[personal profile] troisroyaumes 2006-11-03 02:03 am (UTC)(link)
Oh, and I should add that the standard is that if it's just "greater than" then you draw the boundary as a dotted line, while if it's "greater than or equal to" then you draw the boundary as a solid line.

[identity profile] themadpoker.livejournal.com 2006-11-03 02:04 am (UTC)(link)
But since I don't know x does that mean I should just put the y-intercept as 6? That's the part that confused me.
troisroyaumes: Painting of a duck, with the hanzi for "summer" in the top left (Default)

[personal profile] troisroyaumes 2006-11-03 02:11 am (UTC)(link)
Yup! The standard way to graph a line, given the equation y = mx + b (where the values of m and b are given) is that the slope of the line is m and the y-intercept is b. In the case of y = 6 + x, m = 1 and b = 6.
troisroyaumes: Painting of a duck, with the hanzi for "summer" in the top left (Default)

[personal profile] troisroyaumes 2006-11-03 02:19 am (UTC)(link)
Glad to help! ^_^